Given: Step1: HBr(g) + O2(g) = HOOBr(g) Slow Step2: HBr(g) + HOOBr = 2HOBr(g) Fa

Question

Given: Step1: HBr(g) + O2(g) = HOOBr(g) Slow Step2: HBr(g) + HOOBr = 2HOBr(g) Fast Step3: 2HBr(g) + 2HOBr = 2H2O(g) Fast
What is the molecularity of the third element step3 Given: Step1: HBr(g) + O2(g) = HOOBr(g) Slow Step2: HBr(g) + HOOBr = 2HOBr(g) Fast Step3: 2HBr(g) + 2HOBr = 2H2O(g) Fast
What is the molecularity of the third element step3 Step1: HBr(g) + O2(g) = HOOBr(g) Slow Step2: HBr(g) + HOOBr = 2HOBr(g) Fast Step3: 2HBr(g) + 2HOBr = 2H2O(g) Fast
What is the molecularity of the third element step3

Explanation / Answer

The molecularity of the raction means the stoichiometric sum of coefficients of all the reactants that come together and forms products.

Simply the total number of reactants are called as molecularity.

In third reaction, total 4 reactants ( 2 of HBr & 2 of HOBr ) are involved . Therefore molecularity of last reaction is 4.

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