The specific gravity of gasoline is approximately 0.70. i) Determine the mass (k

Question

The specific gravity of gasoline is approximately 0.70. i) Determine the mass (kg) of 500 liters of gasoline. (ii) The mass flow rate of gasoline exiting a refinery tank is 1386 kg/min. Estimate the volumetric flow rate in liter/s. (iii) Gasoline and kerosene (specific gravity 0.82) are blended to obtain a mixture with a specific gravity of 0.78. Calculate the volumetric ratio (volume of gasoline/volume of kerosene) of the two compounds in the mixture, assuming V_ blend = V_ gasoline + V_ kerosene. Given: density of water = 1 g/cm^3

Explanation / Answer

Specific gravity of gasoline = density of gasoline/density of water

Density of gasoline = 0.70*1g/cm3= 0.70g/cm3=0.70 kg/litre

1) 1 litre contains 0.70 kg gasoline

500 litres contain350 kg gasoline

2)mass flow rate = 1386 kg /min

Volumetric flow rate = mass flow rate/density = (1386kg/min)/(0.70kg/litre)=1980liter/min

3) let 1 be gasoline

2 be kerosene

Spg be specific gravity

V1 be volume of gasoline

v2 be volume of kerosene

v be volume of blnd

spg1*v1 + spg2 *v2 = spg *v

0.70*v1+0.82*v2=0.78*v..........(1)

v1+v2 =v......(2)

solving 1 &2

v1= 0.3333

v2=0.6666

v1/v2=volume of gasoline/volume of kerosene = 0.5

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