A solution is composed of 1.40 mol cyclohexane (Pcy=97.6 torr) and 2.10 mol acet

Question

A solution is composed of 1.40 mol cyclohexane (Pcy=97.6 torr) and 2.10 mol acetone (Pac=229.5 torr). What is the total vapor pressure Ptotal above this solution? Express your answer with the appropriate units. Ptotal = 177 torr

If a third volatile component had been present in this solution, the total pressure would be calculated in a similar manner but would involve three terms rather than two. For example, Ptotal=PA+PB+PC=XAPA+XBPB+XCP

C Part C As you saw in Part B, the vapor above the cyclohexane-acetone solution is composed of both cyclohexane vapor and acetone vapor. What mole fraction of the vapor above the solution, Xcy(vapor), is cyclohexane?

Explanation / Answer

C)

mole fraction of cyclohexane in solution phase = 1.40 / (1.40 + 2.10) = 0.4

Pcyclo = 0.4 x 97.6 = 39.04 torr

Pcyclo = mole fraction in vaporu phase x total pressure

39.04 = mole fraction in vaporu phase x 177

mole fraction in vaporu phase = 0.220

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