For your titrations of the hydrogen peroxide in a new bottle, record the followi

Question

For your titrations of the hydrogen peroxide in a new bottle, record the following data in the table below. If you had to perform three fine titrations, disregard the one that was different.

Data Analysis

For your titrations of the hydrogen peroxide in a new bottle, calculate the molarity of the new hydrogen peroxide solution using the average volume of permanganate solution dispensed in the fine titrations. If you had to perform three fine titrations, disregard the one that was different.

Calculate the mass percent of the hydrogen peroxide in the new bottle. The molar mass of H2O2 is 34.0147 g/mol and the density of the solution is 1.000 g/mL.

Experiment 2: Titrate the Hydrogen Peroxide in an Old Bottle

Lab Results

For your titrations of the hydrogen peroxide in a new bottle, record the following data in the table below. If you had to perform three fine titrations, disregard the one that was different.

Data Analysis

For your titrations of the hydrogen peroxide in an old bottle, calculate the molarity of the old hydrogen peroxide solution using the average volume of permanganate solution dispensed in the fine titrations. If you had to perform three fine titrations, disregard the one that was different.

Calculate the mass percent of the hydrogen peroxide in the old bottle. The molar mass of H2O2 is 34.0147 g/mol and the density of the solution is 1.000 g/mL.

initial volume of .2M KMnO4 in the burette (mL) 50.00 volume of hydrogen peroxide solution added to the flask (mL) 10.00 volume of .2M KMnO4 dispensed in the coarse titration (mL) 19.06 volume of .2M KMnO4 dispensed in the first fine titration (mL) 18.02 volume of .2M KMnO4 dispensed in the second fine titration (mL) 18.01

Explanation / Answer

Average volume of KMnO4 = (18.01+18.02)/2

= 18.015 ml

Molarity of KMnO4 = 0.2 M

Milli-Moles of KMnO4 = 0.2 * 18.015

Consider Molarity of H2O2 = x M

Following is the balanced reaction

2 KMnO4 + 5 H2O2 + 3 H2SO4 ----> 2 MnSO4 + K2SO4 + 5 O2 + 8 H2O

Hence ( Moles of KMnO4 )/2 = (Moles of H2O2 )/5

5* moles of KMnO4 = 2* Moles of H2O2

  5 * 0.2 * 18.015 = 2 * x *10

x= 0.9 M

Hence Molarity of H2O2 is 0.9M

Now mass%

1000 ml of H2O2 solution contain 0.9 moles of H2O2 . Hence wt of H2O2 =0.9 * 34 = 30.6 gm

wt of H2O2 sloution = 1000 gm

  

mass % of H2O2 = 3%

  

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