Determine Delta G degree_rx (in kJ) for this reaction at 316.79 K. Assume Delta

Question

Determine Delta G degree_rx (in kJ) for this reaction at 316.79 K. Assume Delta H degree_f and S degree do not vary as a function of temperature. Report your answer to two decimal places Determine the equilibrium constant for this reaction at 316.79 K. report your answer to three significant figures in scientific notation. If the partial pressure of N_2 is 5.31 atm, determine Delta G (in kJ) for this reaction at 316.79 K. Report your answer two decimal places in standard rotation (i.e. 123.5 kJ)

Explanation / Answer

Q2.

for the equilibrium constant:

dG = -RT*ln(K)

-252.81*1000 = -8.314*(316.79)*ln(K)

K = exp(252.81*1000/8.314/316.79)

K = 4.8602*10'^41

Q3.

partia pressure ofN2 = 5.31 atm

dG for reaction...

so

Kp = Kc*(RT)^dn

Kp = ( 4.8602*10^41)(0.082*316.79)^-1 = 1.8709*10^40

3Li(s) + N2 = Li3N(s)

Kp = 1/P-N2

1.8709*10^40 = P-N2

P =5.3450*10^-41 atm

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