Determination of Specific Heat of a Metal Trial 1 Mass of water: 4g -41.4g = 37.

Question

Determination of Specific Heat of a Metal

Trial 1

Mass of water: 4g -41.4g = 37.4g water

Mass of metal: 47.8g

Trial 2

Mass of water:4.0 g-41.1g = 37.1 g water

Mass of metal:47.9 g

Temperature change of water:23 deg C to 34 deg C=+11 deg C

Temperature change of metal:86 deg C to 35 deg C = -51 deg C

Temperature change of water: Initial water temp 23 deg C to 35 deg C=+12 deg C

Temperature change of metal:86 deg c to 35 deg C= -51 deg C

Trial 3

Mass of water:

4.0g-41.1g = 37.1 g water

Mass of metal:48.0 grams

Temperature change of water: 23 deg C to 35 deg C=+12 deg C

Temperature change of metal:85 deg C to 35 deg C=-50 deg C

Trial 1

1.Specific heat of metal:?

Trial 2

2.Specific heat of metal:?

Trial 3

3.Specific heat of metal:?

4.Identity of unknown metal (use Table 1 for reference):?

5.Why is ?Tmetal < 0?

.Why is ?Twaterl > 0?

Explanation / Answer

Trial 1:

mmetal*Cmetal*dTmetal +mwater*Cwater*dTwater=0

47.8*C*-51+37.4*4.18*11=0

C=0.705 J/g.?

Trial 2:

mmetal*Cmetal*dTmetal +mwater*Cwater*dTwater=0

47.9*C*-51+37.1*4.18*12=0

C=0.762 J/g.?

Trial 3:

mmetal*Cmetal*dTmetal +mwater*Cwater*dTwater=0

48.0*C*-50+37.1*4.18*12=0

C=0.775 J/g.?

4. Metal from chart: Aluminium( closect element, error due to heat lost to enviroment)

5.?T<0 for metal because heat is removed from it.

?T>0 for water because heat is given to it.

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