I have Zinc Sulfate Heptahydrate (mol wt 287.541g/mol). I want to make a medicat

Question

I have Zinc Sulfate Heptahydrate (mol wt 287.541g/mol). I want to make a medication with the same amount/percentage of Zinc elemental as Zinc Citrate Dihydrate (mol wt 610.368g/mol). Basically I need to know how much Zinc Sulfate Heptahydrate I need to add to each pill to ensure I get the same amount of Zinc elemental (active ingredient) as an equivalent amount of Zinc Citrate Dihydrate. The amount of Zinc elemental I need per pill is the amount that would be in 30mg of Zinc Citrate Dihydrate.

Please show full work step by step.

Explanation / Answer

Zinc Sulfate Heptahydrate = 287.541 g/mol

Zinc Citrate Dihydrate = 610.368 g/mol

Zin mass = 65.38 g/mol

First, identify how much zinc is in 30 mg of Zinc Citrate Dihydrate:

Fraction fo inc = mass of Zinc / total mass 65.38/610.368 = 0.1071157

so... for 30 mg --> 0.1071157*30 = 3.213 mg of Zn in that pill

now, if we try to substitute this for the heptahydrate:

mass of hydrate reruired..

fraction of Zn in Heptahydrate = 65.38 /287.541 = 0.2273

now...

mass of hepthydrate required for 3.213 mg of Zn:

Mass of Zinc Sulfate Heptahydrate --> 3.213 / 0.2273 = 14.13 mg of ZnS*7H2O

so..

that will be the mix, 14.13 mg of the heptahydrate instead of 30 mg of the citrate

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