Threorime is an amino acid which cantains an asymmetric carban and can rotate pl

Question

Threorime is an amino acid which cantains an asymmetric carban and can rotate plane polarized light (a) True (b) False In secondary protein structures, the protein folds into specific peptide backbone conformations. The protein is stabilized by hydrogen bonding and other non-covalent interactions between atoms in peptide backbone (a) True (b) False Carbonyl chloride (COCI_2), also called phophogene, was used in World War I as a poisonous gas. The equilibrium concentrations for the reaction between carbon monoxide and molecular chlorine to from carbonyl chlorine; CO_(g) + Cl_2(l) doubleheadarrow COCl_2(g) at 74 degree are [CO] = 1.2 times 10^-3 M, [Cl_2] = 0.054 M, and [COCl_2] = 0.14 M. The equilibrium constant (Kc) is (a) 1.16 times 10^2 (b) 1.16 times 10^-2 (c) 2.16 times 10^2 (d) 2.16 times 10^-2 (e) None of the above Which of these amino acids has an side chain? Glutamine Tryptophan Histidine Proline None of the above The pH of a solution of 0.005 M aqueous solution of calcium hydroxide is 1 4 6 12 None of the above If the rate of a reaction increases by a factor of 512 when the concentration of reactant increase by a factor of 8, the order of the reaction with respect to this reactant is 2 3 4 5 None of the above. Monoamino-monocarboxylic acids exist in aqueous solution as zwitterions. What zwiterrion? Which of the following amino acids can be classified as essential Threonine Proli Serine Glutamic acid None of the above The hydrogen ion concentration of a solution of 0.001M magnesium hydroxide is M 2 times 10^-11 M 5 times 10^-12 M 2x 10^-13 M None of the above Draw the complete reaction between alanine and glycine or any two amino acids re the formation peptide bond.

Explanation / Answer

3.CO(g) + Cl2(l)--->COCl2(g)

Kc= [COCl2]/[CO] [Cl2]

Kc = 0.14/1.2×10-3 × 0.054

Kc = 2.16 × 103

4.Proline.Its an alpha-imino acid.only amino acid with a secondary amine.

5.CaOH2---> Ca2+ + 2OH-

So one mole of CaOH2 disassociates to give 2 moles of hydroxide ion.

SO,concentration of OH- in the solution = 2×0.005M = 0.01M

pOH = -log[OH-]

pOH = -log(0.01)

pOH = -(-2) = 2

pH = 14-pOH

pH = 14-2 = 12

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