1.(5 points) Calculate the concentration (in mM) of a solution prepared by disso
ID: 477554 • Letter: 1
Question
1.(5 points) Calculate the concentration (in mM) of a solution prepared by dissolving 3.02g of solid MgSO4 (Formula Weight: 120.37g/mole) in dH2O (final volume is 50mL)?
2.(15 points) If you dissolve 45mg glucose (Formula Weight: 180.16g/mole) in 1.0mL of water: a.What is the concentration of glucose in M and µM? b.If you take 5mL of this solution and dilute it to 250mL what is the concentration of the glucose in the resulting solution in µM? c.How many nanomoles of glucose are present in 10mL of the diluted solution?
3. (5 points) Convert the concentration below to mM and µM: a. 240mg of sucrose (Formula Weight: 342.30g/mole) per 70mL
4.(10 points) What molarity of HCl stock solution is needed so that 0.5mL of this stock solution diluted to 0.05L will yield 50mM?
5.(10 points) You have to make 100mL of 0.05M HCl from a 10M HCl stock solution, but the only measuring devices available are 100mL graduated cylinders and 10mL serological pipets. How could you accurately make the dilute HCl solution (see pgs. 8-12 in your Laboratory Manual)?
6. (25 points) You have a 0.15M stock solution of NaCl (Formula Weight: 58.4g/mole), a 0.5M stock solution of glucose (Formula Weight; 180.2g/mole), and a bottle of solid Tris base (Formula Weight: 121.1g/mole). How would prepare (be specific) 250mL of a single solution containing 50mM Tris, 25mM glucose, and 30mM NaCl.
7.(10 points) Describe how you would prepare 25mL of a 0.0250 M stock solution of potassium chloride (Formula Weight: 74.55g/mole). Using this stock solution, describe how you would prepare 100mL of the following dilutions: 2.5mM and 500M
8.(10 points) How many milligrams of MgCl2 (Formula Weight: 95.211g/mole) are contained in 250mL of 150mM MgCl2?
9.(10 points) What is the molar concentration of sodium chloride (Formula Weight: 58.44g/mole) in a 12.5% (w/v) solution?
Explanation / Answer
1. Molar concentration is defined as moles of solute per litre of solution.
Moles of MgSO4:- given mass/molar mass=3.02/120.37
Moles=0.025
Volume=50/1000=0.050
Concentration in molar=0.5
Concentration in mM=0.5×1000=500 mM
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