1. your car is approaching a curve of radius 40 meters. te manufacturer of your

Question

1. your car is approaching a curve of radius 40 meters. te manufacturer of your car's tires says that the can create a centripetal force (through friction) of 12, 100 N with the ground

A) if you car has a mass of 1000 kg how fast can you take the corner without skidding

B) on an icy day the friction of your tires can only exert a centripetal force of 900N, how fast can you take the same corner ?

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2) the moon has a mass of 7.3 x 10^22 kg and orbits the earth at an average radius of 3.8 x 10^8 meters. it completes one orbit around the earth in about 27.3 days

what is the moon's linear velocity? what is the moon's centripetal acceleration?

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3. a body of mass 0.1 kg is been rotated in a circular path of diameter 1 m on a frictionless horizontal plane bye means of a string. it performs 10 revolutions in 31.4 sec. calculate the centripetal force acting on the body

Explanation / Answer

Number 1)

Part A)
Apply F = mv2/r

12,100 = 1000(v2)/40

v = 22 m/s

Part B)

900 = 1000(v2)/40

v =6 m/s

Number 2)

Part A)
v = d/t = 2pir/t

t = 27.3 days which is 2358720 sec

v = 2pi(3.8 X108)/2358720

v = 1012 m/s

Part B)

a = v2/r

a = (1012)2/(3.8 X 108)

a = 2.70 X 10-3 m/s2

Number 3)

F = mv2/r

v = d/t = 10(2)(pi)(.5)/3.14

v = 10 m/s

F = (.1)(10)2/.5

F = 20.0 N

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