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A flask is charged with 0.140 mol of A and allowed to react to form B according

ID: 476009 • Letter: A

Question

A flask is charged with 0.140 mol of A and allowed to react to form B according to the following hypothetical gas-phase reaction.

The following data are collected.


(a) Calculate the number of moles of B at each time in the table.

0 s
___ mol

40 s
___ mol

80 s
___ mol

120 s
___ mol

160 s
___ mol



(b) Calculate the average rate of disappearance of A for each 40 s interval, in units of mol/s.

0 - 40 s
___ mol/s

40 - 80 s
____ mol/s

80 - 120 s
___ mol/s

120 - 160 mol/s
___ mol/s

times (s) 0 40 80 120 160 moles of A 0.140 0.066 0.048 0.026 0.024

Explanation / Answer

a) from the reaction it is clear rate of disappearence = rate of appearence

0s = 0 mol

40 s = 0.14 - 0.066 = 0.074 moles

80s = 0.14 - 0.048 = 0.092 moles

120 s = 0.14 - 0.026 = 0.114 moles

160 s = 0.14 - 0.024 = 0.116 moles.

b) averate rate = change in concentration / time taken

0 - 40 s

rate = (0.14 - 0.066 /40) = 0.00185 M/S

40 -80 s

rate = (0.066 - 0.048 / 40) = 0.00045 M/s

80 -120 s

rate = (0.048 - 0.026 / 40) = 0.00055 M/s

120-160s

rate = (0.026 - 0.024 /40) = 0.00005 M/s

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