Using the data below,determine the number of classes,the width of the classes, a
ID: 399391 • Letter: U
Question
Using the data below,determine the number of classes,the width of the classes, and the boundaries for the following information: 1261 1280 1290 1312 1341 1355 1357 1360 1414 1436 1479 1492 1. 339 34 395 457 478 501 521 556 583 595 596 604 1535 650 655 669 703 730 763 788 789 789 802 822 851 864 883 883 890 934 951 969 985 993 997 1025 1028 1036 1044 1087 1091 1126 1176 1199 1199 1237 1242 16 153 96 103 115 124 148 164 212 265 288 1653 17 183 1864 192 1965 1972 2032 1018 2, Determine the frequency distribution for the data above using the classes and boundaries identified in #2 3, what is the relative frequency for each class using the frequency distribution from #3? 4. In manufacturing why is it not practical to test every item made? (think about class discussion about light bulbs or powerlifting bars) S. The BW Company took a sample of their employees to determine remaining vacation time balancesExplanation / Answer
1.
The minimum value is 2 and the maximum is 2032. The overall width is 2032 - 2 +1 = 2031. Let us take 100 as the class width and 21 classes. The class intervals thus formed is shown below.
2.
(3)
4.
Testing every item is not feasible because testing is not free of cost. There can be several costs associated with testing such as human hours, cost of utilities, energy cost. On top of that, if the testing is destructive in nature, then it causes rejection of the test pieces. If there is 100 percent or too many test samples taken, then the cost of testing will surpass the cost saved due to poor quality.
Class From To 1 2 101 2 102 201 3 202 301 4 302 401 5 402 501 6 502 601 7 602 701 8 702 801 9 802 901 10 902 1001 11 1002 1101 12 1102 1201 13 1202 1301 14 1302 1401 15 1402 1501 16 1502 1601 17 1602 1701 18 1702 1801 19 1802 1901 20 1902 2001 21 2002 2101Related Questions
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