Using the configurations shown in the figures below, an object hanging in air (F

Question

Using the configurations shown in the figures below, an object hanging in air (Figure 1)causes the scale to balance at 0.042 kg.

When the object is submerged in water (Figure 2), the scale balances at 3.5×10?2 kg. For all calculations, use g = 9.8 m/s2.

A) Find the weight of the object in the air .

B) Find the apparent weight of the object when submerged in the water.

C) What is the volume of the object? For the density of water, use ?water = 103 kg/m3 = 1000 kg/m3

D) What is the density of the object?

Explanation / Answer

(A) W = m g = 0.042 x 9.8 = 0.412 N

(B) _apparnet = (3.5 x 10^-2)(9.8) = 0.343 N

(C) Buoyant force, Fb = 0.412 - 0.343

= 0.069 N  

and Fb = rho V g

0.069 = 1000 V (9.8)

V = 7.04 x 10^-6 m^3

(D) density = m / V

= (0.042)/(7.04 x 10^-6)

= 5965 kg /m^3  

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.