Write a menu-driven program, which uses a 3 x 4 array, and offers 4 choices as f

Question

Write a menu-driven program, which uses a 3 x 4 array, and offers 4 choices as follows:

using arrays and pointers to functions.

cout << " Enter a choice: "

        << " 0 Print the array of grades "

        << " 1 Print sum of each row "

        << " 2 Print sum of each column "

        << " 3 Print average of all grades "

        << " 4 End program ? ";

Each choice should represent a function and functions are selected through an array of pointers to functions as shown below:

   void ( *processGrades[ 4 ] )( int [][ EXAMS ], int, int )

                      = { printArray,rowSum,colSum,average };

Declaring grades:

   int choice = 0,

       studentGrades[ STUDENTS ][ EXAMS ] = { { 77, 68, 86, 73 },

                                              { 96, 87, 89, 78 },

Making choice:                                { 70, 90, 86, 81 } };

   while ( choice != 4 ) {

      do {

         printMenu();

         cin >> choice;

      } while ( choice < 0 || choice > 4 );

      if ( choice != 4 )

         ( *processGrades[ choice ] )( studentGrades, STUDENTS, EXAMS )

      else

         cout << "Program Ended. ";

Write the above-described program

Explanation / Answer

#include<iostream>

using namespace std;

void printMenu()

{

cout << " Enter a choice: "

<< " 0 Print the array of grades "

<< " 1 Print sum of each row "

<< " 2 Print sum of each column "

<< " 3 Print average of all grades "

<< " 4 End program ? "<<" ";

}

void printArray (int a[3][4],int s,int e)

{

int i=0,j=0;

for (i=0;i<s;i++)

{

for (j=0;j<e;j++)

cout<<a[i][j]<<" ";

cout<<" ";

}

}

void rowSum (int a[3][4],int s,int e)

{

int i=0,j=0,sum=0;

for (i=0;i<s;i++)

{ sum=0;

for (j=0;j<e;j++)

sum+=a[i][j];

cout<<i<<"th row sum="<<sum<<" ";

}

}

void colSum (int a[3][4],int s,int e)

{

int i=0,j=0,sum=0;

for (i=0;i<e;i++)

{ sum=0;

for (j=0;j<s;j++)

sum+=a[j][i];

cout<<i<<"th col sum="<<sum<<" ";

}

}

void average (int a[3][4],int s,int e)

{

int i=0,j=0,sum=0;

for (i=0;i<e;i++)

{

for (j=0;j<s;j++)

sum+=a[j][i];

}

cout<<i+1<<"average="<<(float)sum/(s*e)<<" ";

}

int main()

{

int choice,STUDENTS=3,EXAMS=4;

int studentGrades[ 3 ][ 4 ] = { { 77, 68, 86, 73 },

{ 96, 87, 89, 78 },

{ 70, 90, 86, 81 } };

void ( *processGrades[ 4 ] )( int [3][ 4 ], int, int )= { printArray,rowSum,colSum,average };

do

{

printMenu();

cin>>choice;

if ( choice != 4 )

( *processGrades[ choice ] )( studentGrades, STUDENTS, EXAMS );

else

cout << "Program Ended. ";

}

while (choice>=0 && choice<4);

return 0;

}

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