See Image Below CAPAM Homework Help Ask A Q Thr C fi ou.edu law/dci19Oct99.probl

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CAPAM Homework Help Ask A Q Thr C fi ou.edu law/dci19Oct99.problem?symb uploaded%2fohiou%2fld348015cd5835236oucapa2%2fdefault 1388360754%2esequence. Ohiou9 E Apps G Hw Help D wileyplus R ON-CAPA. b phyticsbgok Blackboard Learn A Email a Amazon Student A OUCU CC payment G Glyde PVIOECHter Discover E ESPN Premier Fant, CUR a Dailybreak Notes Bookmark Evaluate Communicate Print o Info Course Contents Week 10 Magnetic Field due to Three Parallel Wires Magnetic Field due to Three Parallel Wires Due in 10 hours, 32 minutes Three long parallel wires a at the corners of a square of side 5.0 cm and each carry a current in the same direction of 84.0 A. The wires are shown as black dots in the figure and are perpendicular to the page or screen. What is the magnitude of the magnetic field at the corner where there is no wire? Submit Answer Tries 0/10 Preferences on what is marked as NEW Threaded View Chronological View Sorting/Filtering options Export? Mark NEW posts no longer ne NEW Esteb Rodriguez 705111:oh Reply (Wed Mar 26 03:54:06 p 2014 (EDT Aren't we supposed to View this user's personal information page Current discussion settings: 1. Display All posts 2. Not new Once marked not NEW Change? Preferences on what is marked as NEW Threaded View Chronological View Sorting/Filtering options Export? Mark NEW posts no longer ne Post Discussion Send Feedback

Explanation / Answer

fourth cornor is at a distance of 5 cm from two wires

so magntic ield B due to satraight wire at adistance r is given by B =u0i/2pir

B1 due to one wire is = B1 = 4pi*10^-7 * 84/(2pi* 0.05) = 0.336 mT

B2 is also same , but acts at right angelt o B1

so Befff of these two is Beff^2 = B1^2 + B2^2   = sqrt 2 * B1

Beff = 1.414* 0.336 = 0.4751 mT

B3 due to diaginal wire is,

its diatcne is sqrt(5^2 + 5^2) = 1.414* 5 = 0.0707 m

so B3 = 4pi*10^-7 * 84/(2pi* 0.0707) = 0.2376 mT

thus finally Bnet = Beff + B3

Bnet = 0.4751+ 0.2376 = 0.7127 mT or 7.127*10^-4 T

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