I got 9.2 x 10^-5 and 1.2 x 10^-6 Both were wrong... Please help, I dont have ma

Question

I got 9.2 x 10^-5

and 1.2 x 10^-6

Both were wrong...

Please help, I dont have many attempts left.

I tried

B= uo*I / 2*pi*r

Where r= d/2 + midpoint

for the wire 1

and r= d/2 - midpoint

for wire 2

A long pair of insulated wires serves to conduct 22.5Aof dc current to and from an instrument. Part A If the wires are of negligible diameter but are 2.8 mm apart, what is the magnetic field 10.0 cmfrom their midpoint, in their plane (Figure 1) ? Express your answer using two significant figures. Bnet =   T   SubmitMy AnswersGive Up Incorrect; Try Again; 3 attempts remaining Part B Compare to the magnetic field of the Earth of 5.0

Explanation / Answer

A.)Let the left wire be wire 'A' and right wire be wire 'B'.

Now,wire 'A' is at a distance of 10cm + 2.8/2 mm from the given point = 10.14 cm

so, field due to wire 'A' at point = uo * I / (2Pi*r) = (4*Pi * 10^-7)/(2*Pi*10.14*10^-2) = 4.43 * 10^-5 T

Now,wire 'B' is at a distance of 10cm - 2.8/2 mm from the given point = 9.86 cm

so, field due to wire 'A' at point = uo * I / (2Pi*r) = (4*Pi * 10^-7)/(2*Pi*9.86*10^-2) = 4.56 * 10^-5 T =

So, difference is 1.3*10^-6 T

B.) nearly 1/39 of earth's magnetic field.

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