A given system has the equipotential surfaces shown in the figure ( Figure 1 ) .

Question

A given system has the equipotential surfaces shown in the figure (Figure 1) . A given system has the equipotential surfaces shown in the figure (Figure 1) . A given system has the equipotential surfaces shown in the figure (Figure 1) . A given system has the equipotential surfaces shown in the figure (Figure 1) . Part A What is the magnitude of the electric field? E =
V/m Part B What is the direction of the electric field? ? =
? from the +x axis Part C What is the shortest distance one can move to undergo a change in potential of 3.50V ?
d =
mm
Part A What is the magnitude of the electric field? E =
V/m Part B What is the direction of the electric field? ? =
? from the +x axis Part C What is the shortest distance one can move to undergo a change in potential of 3.50V ?
d =
mm
Part A What is the magnitude of the electric field? E =
V/m Part B What is the direction of the electric field? ? =
? from the +x axis Part C What is the shortest distance one can move to undergo a change in potential of 3.50V ?
d =
mm
Part A What is the magnitude of the electric field? E =
V/m Part B What is the direction of the electric field? ? =
? from the +x axis Part C What is the shortest distance one can move to undergo a change in potential of 3.50V ?
d =
mm
Part A What is the magnitude of the electric field? E =
V/m Part A What is the magnitude of the electric field? E =
V/m E =
V/m E =
V/m Part B What is the direction of the electric field? ? =
? from the +x axis Part B What is the direction of the electric field? ? =
? from the +x axis ? =
? from the +x axis ? =
? from the +x axis Part C What is the shortest distance one can move to undergo a change in potential of 3.50V ?
d =
mm
Part C What is the shortest distance one can move to undergo a change in potential of 3.50V ?
d =
mm
d =
mm d =
mm of 1 A given system has the equipotential surfaces shown in the figure (Figure 1) . Part A What is the magnitude of the electric field? E =
V/m Part B What is the direction of the electric field? ? =
? from the +x axis Part C What is the shortest distance one can move to undergo a change in potential of 3.50V ?
d =
mm
of 1

Explanation / Answer

A)

Ex = delta V/(x2-x1) = -10/0.04 = -250 N/c

Ey = delta V/(x2-x1) = -10/0.02 = -500 N/c


E = sqrt(Ex^2 + Ey^2) = 559 N/c

B)

theta = tan^-1(Ey/Ex) = 63.43+180 = 243.43 degrees with +x axis in conter clockwise direction.


C) delta V = E*d

d = delta V/E

= 3.5/559

= 6.26*10^-3 m

= 6.26 mm

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