A long jumer jumps at A person pull A roller coster Please try to give all of th

Question

A long jumer jumps at

A person pull

A roller coster

Please try to give all of the answers,I wil give 5 stars

A long jumper at an angle of 25 degree to the ground at speed of 14 m s. Assuming that the motion ot the long jumper is like a projectile. how far does she jump What is the max height of jump A person pulls upward on a 15kg box with a force of 160n What is the net force on the box? What is the the acceleration on the box F = ma A roller kater moves down an incline of length 25.0 m with an initial velocity of 3.5 m s in 2.5 s Assuming no friction, at what angle is the incline above the horizontal? x - x = v t + 1 2 at a = s sin theta

Explanation / Answer

a) distance = u^2 * (sin (2theta)) / g

= 14^2 * sin(50) / 9.8

= 15.32m

Max height of jump = v^2 sin^2 theta / (2g)

h = 1.78m

b) net force = mg - F

= 15*9.8 - 160

= -13

net force = 13N upwards

accelertion = 13/15

= 0.866m/s^2

c)25 = 3.5*2.5 + 0.5 * 9.8 * sintheta * (2.5)^2

theta = 32.04 degrees

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