Suppose that we have a glass rod surrounded by air with the left end ground to a
ID: 3892757 • Letter: S
Question
Suppose that we have a glass rod surrounded by air with the left end ground to a convex hemisphere 2-cm radius. If a point source is located 6 cm to the left of the hemisphere's vertex, where will its image appear? If the glass rod (Problem 1) is immersed in water, determine the new location of the image of the point source A point source S is located on the axis of, and 30cm from a plano-convex thin lens. Suppose that the glass lens is immersed in air and that is has a radius of 5 cm. Determine the location of the image when the flat surface is toward and when the curved surface is toward S. What must be the focal length of a positive thin lens if the object and the image distances are to be 90cm and 45 cm respectively? Imagine that you'd like to look through a lens at your pet parakeet and see it standing right-side up but shrunk to one-third its normal height. Designing the focal length as f, determine the kind of lenses needed, as well as the object and image distances in terms of f.Explanation / Answer
1)n2/di -n1//do =(n2-n1)/r
n2=1.5,n1=1.33
give R=2cm
1.5/di-1/6 =(0.5)/2
1.5/di=0.416
di=3.6cm
Now refraction from glass rod to
u1/u2=di/di1
1.5/1=3.6/di1
di1=2.4cm
image distance is 3.4cm
2)When lens is placed in water
1.5/di-1.33/d0=(1.5-1.33)(1/R)
1.5/di-1.33/6=(0.17/2)
1.5/di-0.22=0.085
1.5/di=0.305
di=4.91
again from lens to water
1.33/di-1.5/2.4=(1.33-1.5)(1/2)
1.33/di-0.625=(-0.17/2)
1.33/di=-0.085+0.625
1.33/di=0.54
di=2.46cm
Final Image distance in water is 2.46cm
3)
a) Convex surface
1/2.5=1/30 +1/di
1/di=0.366
di=2.72cm
b)when plane surface is facing
0=1/30+1/di
di=-30cm
4)1/di +1/do =1/f
1/90 +1/45=1/f
f=30cm
5)hi/ho=-di/do
-ho/3/h0=-di/do
do=3di
1/f=1/di +1/3di
f=3/4di
di=4/3f
do=4f
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