Please help me answer this questions and develop a logical network design Comput

Question

Please help me answer this questions and develop a logical network design

Computer Dynamics is a software development company that has a 300-computer network. The company is located in three adjacent five-story buildings in an office park with about 100 computers in each building. The LANs in each building are similar, but one building has the data center on the second floor. There are no other office locations. The current network is poorly designed for its current needs and must be completely replaced. Develop a logical network design for this enterprise campus that considers the seven network architecture components. You will need to make assumptions, so be sure to document them and explain why you have designed the network in this way.

Explanation / Answer

Given that the company consists of three buildings that are five story buildings .

The networking is done in a company so, privacy must be the most important factor for considering the physical network.

Company employees need to communicate with each other , so, private IP address range must be set. IP address range is useful in communicating within the LAN network.

The range of Private IPV4 address is given by:-

(1.1) 10.0.0.0 – 10.255.255.255
(1.2)   172.16.0.0 – 172.31.255.255
(1.3) 192.168.0.0 --192.168.255.255

Another thing that we need to consider is the concept of subnetting. Subnetting is used to devide the networks among the buildings that leads to the effective utilization of IP address.

Here we need to calculate the no. of subnets for the subnetting.

No. of subnets will be equal to the no. of buildings that is equal to 3

Also, the no. of host needed is equal to the no. of computer available in each building that is equal to 100.

So, no. of subnets =3

No. of hosts=100

2^n - 2 = Number of subnets , here n is number of subnet bits

2^n - 2 = 3 ,
So n = 3 is best suited value
So we need 3 subnet bits

No of bits needed for host
2^2 - 2 = 100
So n = 7 (this will be the best suited value)

So total bits needed for the management is 7 + 3 = 10 and minimum loss of IP address we use range 192.168.0.0

·         So Network Id of whole Network is 192.168.252.0 and it iwll be assigned to data center.

So Network ID of first subnet is 192.168.252.128
First IP address of first building is 192.168.252.129
Last address of First building is 192.168.252.228
Remaining 25 address will be unassigned which can be used in future in first building.
So Network ID of 2nd subnet is 192.168.253.0
First IP address of first building is 192.168.253.1
Last address of First building is 192.168.253.100
Remaining 25 address will be unassigned which can be used in future in 2nd building.
So Network ID of first subnet is 192.168.253.128
First IP address of first building is 192.168.253.129
Last address of First building is 192.168.253.228
Remaining 25 address will be unassigned which can be used in future in first building.

this is the most efficient way to manage the physical network.

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