Hi, please explain step by step how to do it, I really don\'t understand. I have

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Hi, please explain step by step how to do it, I really don't understand. I have included the solution to the question so that you know what the answer is. Please, explain it in details how to solve this :)

B:24 2p. Consider the following forwarding table Destination Network mask Next ho Interface (port number 110.0.0.0 255.0.0.0 m 192.16.7.0 255.255.255.240 193.14.15.193 ml 193.14.5.160 255.255.255.224 m2 193.14.5.192 255.255.255.224 ml 194.17.21.16 255.255.255.255 111.20.18.14 Emo 192.16.7.0 255.255.255.0 111.15.17.32 Emo 194.17.21.0 255.255.255.0 111.20.18.14 mo 0.0.0.0 0.0.0.0 111.30.31.18 m0 Specify next hop and outgoing interface for each of the following destination addresses: 192.16.7.14, 192.16.7.212, 194.17.22.4 och 193.14.5.188 Solution: 192.16.7.14: 193.14.5.193, ml 192.16.7.212: 111.15.16.32, m0 194.17.22.4: 111.30.31.18, m0 (default route) 193.14.5.188: 193.14.5.188, m2 (destination directly connected on the subnet)

Explanation / Answer

We will calculate network address of each address by using the netmask given and then compare with the network address.

1. 192.16.7.14

using netmask 255.255.255.240 , we get network address 192.16.7.0 which matched with 2nd row.

So, next hop is 193.14.15.193 and interface is m1.

2. 192.16.7.212

using netmask 255.255.255.0 , we get network address 192.16.7.0 which matched with 6th row.

So, next hop is 111.15.17.32 and interface is m0.

3. 194.17.22.4

using netmask 0.0.0.0 , we get network address 0.0.0.0 which matched with last row.

So, next hop is 111.30.31.18 and interface is m0.

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