You have conducted an experiment to send some data using a full-duplex link from

Question

You have conducted an experiment to send some data using a full-duplex link from location A to location B, 1500 kilometres away, using the simple reliable data transfer protocol.

The link that you used has 10 Mb/s capacity, you were sending the data in frames of 1000 bytes, and receiving an ACK/NAK frame of 64 bytes.

Assume that you sent 30 frames back-to-back, and that no NAK frames were received in response, so the A-B link's loss probability was 0. What would have been the effective bit rate for this transfer? Show working and express the rate in Mb/s.

Explanation / Answer

The speed of the link is 10Mb/s

so interms of bytes the speed will be

10/8 Megabytes/sec=1.25MBytes/sec (1Byte=8bits)

Then the time taken to send 1000bytes frame will be

1000/(1.25*106)=0.8 milisec

time taken to receive 64bytes ACK frame will be

64/(1.25*106)=0.051milisec

So the total time for sending the frame and receiving an ACK will be

0.8+0.051=0.851milisec

Total Time taken by frame is 0.851ms

30 frames are sent back-to-back

so bit rate for this transfer will be

30/0.851bit/milisec=35.2526439bit/ms

1bit/ms=0.000125Mb/s

so it will be, 35.2526439/0.000125Mb/s=0.0044Mb/s.

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