Declare a two dimensional array of the type char named Table of the size 5 x 4,

Question

Declare a two dimensional array of the type char named Table of the size 5 x 4, i.e. 5 rows and 4 columns. Initialize the array with random capital alphabets and display the array. Display the count of all the vowels in the array. Replace all the vowels with their lowercase counterparts and display the array again. Please note that your output will be different because the array is initialized randomly. S H 2 M I M M Y G O K O B U F I C I U A M B 0 R J U Total Uowels 7 Total Vowels 4 U R S H M i M M Y C i o B u F i a MB Z o R J u W Q U R

Explanation / Answer

#include<iostream.h>
#include <stdlib.h>
#include <time.h>

void main()
{
   char data[5][4];
   int i, j;
   int num;
   int vowel_count;

   srand(time(NULL));
   for (i=0; i<5; i++){
       for (j=0; j<4; j++){
           num = rand() % 26;
           data[i][j] = static_cast<char>( 'A' + num );
       }
   }
   vowel_count = 0;
      
   for (i=0; i<5; i++){
       for (j=0; j<4; j++){
           if (data[i][j] == 'A' || data[i][j] == 'E' || data[i][j] == 'I'
               || data[i][j] == 'O' || data[i][j] == 'U')
           {
               vowel_count++;
           }
           cout << data[i][j] << " ";
       }
       cout << endl;
   }
   cout << "Total vowels: " << vowel_count << endl;  
   for (i=0; i<5; i++){
       for (j=0; j<4; j++){
           if (data[i][j] == 'A' || data[i][j] == 'E' || data[i][j] == 'I'
               || data[i][j] == 'O' || data[i][j] == 'U')
           {
               data[i][j] = data[i][j] + 32;
           }
           cout << data[i][j] << " ";
       }
       cout << endl;
   }
}

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.