10. An electrical engineer has designed a circuit with three light emitting diod
ID: 3790229 • Letter: 1
Question
10. An electrical engineer has designed a circuit with three light emitting diodes (LEDs) placed at various points along the circuit to detect ifa current is running through that section of the circuit. Two switches are also located at various points along the circuit to control the flow ofthe current. The engineer tries closing every combi- nation of switches to see which LEDs will light. She obtains the following results: LED lights as long as switch 1 is open LED2 lights as long as switch 2 is openExplanation / Answer
So its given that there is a circuit with 3 LEDs and 2 Switches. Where switches are controlling flow of current and for various combination of the switched on and off of the 2 switches and the result was as follows and also what it means
1.
LED 1 lights as long as switch 1 is open i.e. LED 1 glows only till the time switch 1 is open or not closed no matter if switch 2 is open or closed
2.
LED 2 lights as long as switch 2 is open i.e. LED 2 glows only till the time switch 2 is open or not closed no matter if the switch 1 is open or closed
3.
LED 3 lights as long as at least one switch is open i.e. LED 3 glows when switch 1 is open or when switch 2 is open or when both switch 1 and 2 are open.(open => not closed).
so on the basis of this result the table is made:
note* the head tells about whether the switch is closed or not
trial no. switch 1 closed switch 2 closed LED 1 LED 2 LED 3 Description 1. Yes Yes Off Off Off since both the switches are closed so none of these LEDs lights 2. Yes No Off On On Since only switch 1 is closed so LED1 do not lights up else do 3. No Yes On Off On Since only switch 2 is closed so LED2 do not lights up else do 4. No No On On On Since none of the switches are closed all 3 LEDs lights upRelated Questions
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