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-Im trying to understand try catch statements.. -with the user enters a string i

ID: 3760443 • Letter: #

Question

-Im trying to understand try catch statements..
-with the user enters a string instead of an int i want the program to cath the (InputMismatchException e) and print out " this is not correct.   
-Im including my code that is not working, please help I dont want the compiler to print out the red inputMismatch .. instead what i said before the "this is not correct:

import java.util.InputMismatchException;
import java.util.Scanner;
public class ExceptionHandling {
  
   public static void main(String[] args)
   {
      
       int digit = numberFromUser();
       int result = sevenModulusN(digit);
       System.out.printf("7 %% %d = %d", digit, result);//illegalFormatConversion
   }

   private static int numberFromUser()
   {
       Scanner input = new Scanner(System.in);
       try{
          
           System.out.print("number: ");
           return input.nextInt();
       }catch(InputMismatchException e)
       {
           System.out.println("This is not correct");
       }
       return input.nextInt();

   }

   private static int sevenModulusN(int number)
   {
       return 7 % number;
   }
      

   }

Explanation / Answer

import java.util.InputMismatchException;
import java.util.Scanner;

public class ExceptionHandling {

   public static void main(String[] args){

       int digit = numberFromUser();
       if (digit != -1) {
           int result = sevenModulusN(digit);
           System.out.printf("7 %% %d = %d", digit, result);
       }
      
   }

   private static int numberFromUser(){
       Scanner input = new Scanner(System.in);
       int in = -1;
       try {
           System.out.print("number: ");
           in = input.nextInt();
       } catch (Exception e) {
           System.out.println("This is not correct");
       }
       return in;
   }

   private static int sevenModulusN(int number) {
       return 7 % number;
   }

}