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ID: 3741325 • Letter: 3
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3/9033 1&content; id-18055095 1&step-n; ASU Home My ASU Colleges& Schools Map & Locations Contact Us Courses Organizations Help QUESTION 11 025 po If the following code snippet were placed inside the main loop of the provided skeleton code for Project 3, based on the information in the project description, what will happen (after one iteration of the main loop)? 1i Sal, 12 call project3 print Nothing will happen The string 12 will be displayed on the simulated UARTs output The string, "o* will be displayed on the simulated UART's output The string. Error: Invalid character will be displayed on the simulated UART's output. QUESTION 12 0.25 po If the following code snippet were placed inside the main loop of the provided skeleton code for Project 3, based on the information in the project description, what will happen (after one iteration of the main loop)? 11 sa0, 12 1i Sal, 0 call project 3_print Nothing will happen The string "12" will be displayed on the simulated UART's output. T "0" will be displayed on the simulated UART's output. The string The string, "Error: Invalid character" will be displayed on the simulated UART's output.Explanation / Answer
11) The code snippet:
li $a1, 12, can be explained as:
li, is used to load the value in the defined register in the above case, that is, loading the integer value 12 in the register $a1, this defines the length of the character that should be read by the register.
Hence the correct answer, in this case will be a. Nothing will happen, because nothing will be going to print on the screen.
12) Here, the code snippet,
li $a0, 12
suggests that integer value is loaded in the register, and tends to printed, but
li $a1, 0, will again set the length to 0, that indicates Nothing will again be displayed on the output
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