3/182 from Engineering Mechanics Dynamics 7 edition The 90-kg man dives from the

Question

3/182 from Engineering Mechanics Dynamics 7 edition

The 90-kg man dives from the 40-kn canoe 11 velocity indicated in the figure is that of the man n- active to the canoe just after loss of contact. If the. man, woman, and canoe are initially at rest, determine the horizontal component of the absolute velocity of the canoe just after separation. Neglect drag on the canoe, and assume that the 60-kg woman remains motionless relative to the canoe. An experimental rocket sled weighs 5200 lb and is propelled by six rocket motors each pulse rating of 8600 lb-sec. The rock.

Explanation / Answer

The twist that makes this problem difficult is that the man's velocity is given w/r/t the canoe, rather than the lake. It's better to think of this as a CM problem -- since the CM was initially at rest, the CM remains motionless even as the man dives. For this to be true,
90kg * (3cos30 - v) = 100kg * v
0.9 * (2.60 - v) = v
2.34 - 0.9v = v
2.34 = 1.9v
v = 1.231 m/s ? velocity of canoe w/r/t water
3cos30 - 1.231 = 1.367 m/s ? velocity of man wr/t water (bonus!)

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