Dear talent students, In this team project (at most 2 persons), you are tying to

Question

Dear talent students,

In this team project (at most 2 persons), you are tying to "hack" a computer by looking for its password. However, the password is secretly nested in a long string. Please write a MIPS assembly code to retrieve the nested password.

To simplify the task, the string that contains the password is provided and is stored in the data segment.

The password is a 6-consecutive digits. For example:

a123456 is NOT a password

123456a is NOT a password

12345 is NOT a password

1234567 is NOT a password

123456 is a password.

Please use the provided MIPS code as a starter and comment your code.

If you work out the project alone, you will receive 20% extra points.

Provided:

.data

MemoryData:
   .asciiz "this is not a password 1122^&*( this is password?987654hello world!!!!1234567"
  
.text
.globl main
main:
# Your code starts here

la $a0, MemoryData # load the head address of "MemoryData" into register $a0
li $v0, 4 # let computer know you about to print out a string
syscall # pring out the string

***Answer must be in MIPS***

Explanation / Answer

#variable declaration

.data

MemoryData: .asciiz "This is not a password 1122^&*(this is password?987654hello World!!!!!1234567 "

result: .asciiz " is a password ."

#main program

.text

li $t2,0 #counter for 6 digits

la $a0,MemoryData #load the given string

li $v0,4 #sytem call to print string

syscall

move $t0,$a0 #move string address into t0

#loop to take each character of the string

loop:lb $t1,0($t0) #each character into t1

move $t4,$t1 #move character into t4 for checking

lb $t3,1($t0) #next character into t3

#is digit check

blt $t4,48,exit1   

bgt $t4,57,exit1

blt $t3,48,exit1

bgt $t3,57,exit1

#compare if the sequence is reverse consecutive

addi $t4,$t4,-1

beq $t3,$t4,next

#compare if the sequence is forward consecutive

addi $t4,$t4,2

bne $t3,$t4,exit1

next:add $t2,$t2,1 #increment counter to display 6 digits

bgt $t2,6,exit1 #greater than 6 then exit

move $a0,$t1 #print consecutive digits

li $v0,11

syscall

#increment $t0 to get next character ang continue loop

exit1:add $t0,$t0,1

beq $t1,10,exit #if the string end then exit

j loop

exit:la $a0,result #add is password at the end of the result

li $v0,4

syscall

li $v0,10 #program end

syscall

Output

This is not a password 1122^&*(this is password?987654hello World!!!!!1234567

987654 is a password .

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