1.what is the minimum number of bits by which the subnest mask must be shifted t

ID: 3720886 • Letter: 1

Question

1.what is the minimum number of bits by which the subnest mask must be shifted to place each of the following IP addresses into different subnets?

which direction?

What is the new subnet mask in CIDR notation? 192.168.2.2/20 192.168.4.2/20 192.168.8.8/ 20

2. what is the minimum number of bits by which the subnet mask must be shifted to each of the following IP addresse into same subnet?

which direction?

what is the new subnet mask in CIDR notation? 200.127.2.2 / 12 200.31.2.2 / 12 200.7.2.2 / 12

Solution:

shift 1 bit on the left hand side(which means towards MSB)

The new subnet mask will be

The subnet mask is all the network bits set to 1

and in CIDR the /n shows that the number of network bits in the network

11111111.11111111.11110000.00000000

255.255.240.0

Shift two bits towards the right hand side

subnet mask

255.240.0.0

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