Suppose you have struct stuff { int x; double y; struct stuff *ptr; }; suppose a

Question

Suppose you have

struct stuff {

int x;

double y;

struct stuff *ptr;

};

suppose a link list of type struct stuff has been generated pointed to by the struct stuff pointer named head. Write a function : double fun (struct stuff * head) that computes the average of all the y's in the link list for which x>0. If no x>0, then return -1.0.

Here's what I have so far. I think I have everything except the situation where no x>0, I'm not sure how to position the return -1.0 instead of the average if there's no x>0 in the link list.

double fun (struct stuff * head)

{

double sum=0;

int count=0;

ptr=head;

while(ptr -> x > 0)

{

sum+=ptr->y;

count++;

ptr=ptr->nextItem;

}

return sum/count;

}

where do I place the return -1.0 if there is no x<0??

Explanation / Answer

Here you should not stop loop if you encounter no x >0. You have to continue the loop until reach the end of the link list. And after loop stops, if there is no x>0 ,i.e., count of nodes which have x >0 is 0, then we return -1.0.

double fun (struct stuff * head)
{
    double sum=0;
    int count=0;
    ptr=head;
    while(ptr)              //until we reaches the end of the loop
    {
       if(x > 0){
            sum+=ptr->y;
            count++;
            ptr=ptr->nextItem;
       }
    }
   if(count == 0){               // here count is zero only if there is no x > 0
       return (-1.0);
   }
   // else we will return the average of y's from the list
    return sum/count;

}

Hope the answer helps !!!

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