I know the output is “Test 4 is at the beginning Test 3 is at the beginning Test

Question

I know the output is “Test 4 is at the beginning Test 3 is at the beginning
Test 2 is at the beginning
Test 1 is at the beginning
Test 2 is at the end Test 3 is at the end
Test 4 is at the end
The result of this function call is 60.”
I’m having a hard time following how this output is determined.
2. What does the following program print? (15 points) # include int prod(int number); int main(void) int x = 4; printf("The result of this function call is %din",prod(x)); return 0; int prod(int number) int printf("test %d at the beginningin", number); if(number== 1) return 1 p (number +1)* prod(number 1); printf("test %d at the endin', number); return p;

Explanation / Answer

program always start from main

x=4

printf("The result of the function call is %d",prod(x)); // It is calling function it pass 4 as argument.

called function:

int prod(int number) // here number receive the argument value 4

printf("Test %d at the begining ",number); // It print Test 4 is at the beginning

if(number==1) // False

p=(number+1)*prod(number-1); // It calls recusrively, (4+1) * prod(4-1) =>p = 5  * prod(3) recursively call

int prod(int number) // here number receive the argument value 3

printf("Test %d at the begining ",number); // It print Test 3 is at the beginning

if(number==1) // False

p=(number+1)*prod(number-1); // It calls recusrively,p = 5  *( (3+1) * prod(3-1)) =>p = 5  * ((4) * prod(2) )recursively call

int prod(int number) // here number receive the argument value 2

printf("Test %d at the begining ",number); // It print Test 2 is at the beginning

if(number==1) // False

p=(number+1)*prod(number-1); // It calls recusrively, p = 5  * (4 * ( 3 * prod(1) ) )recursively call

int prod(int number) // here number receive the argument value 1

printf("Test %d at the begining ",number); // It print Test 1 is at the beginning

if(number==1) // True

retuturn 1; So it return 1 to p recursive call

p=(number+1)*prod(number-1); // It calls recusrively, p = 5  * (4 * ( 3 * 1) ) = 5*4*3 =60 so value of p is 60

printf("test %d at the end ",number); // It runs at what value of number if(number==1) fails, it fails for 2 3 and 4

printf("test %d at the end ",number); so it print

return p; // Here p value send to main calling function

printf("The result of the function call is %d",prod(x)); // It print The result of the function call is 60.

Output:

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