I know the answer to 17 is 12.7, the answer to 18 is 127.6 MeV, and the answer t

Question

I know the answer to 17 is 12.7, the answer to 18 is 127.6 MeV, and the answer to 19 is 5.62 MeV. I need the work.

A neutron star is approximately an enormous stable nucleus composed of neutrons. Estimate the radius of a neutron star which has a mass equal to the Sun's mass M sum = 1.99 times 10 30 kg. Determine the binding energy of . Use M n = 1.008665u, M p = 1.007825u and M = 15.994915u. Radon-222 decays by a decay. Write the reaction for this decay and determine the energy which is released. You will need M = 222.017571u, M = 218.008930u, and M = 4.002603u.

Explanation / Answer

17) 1.c.    A neutron star with twice the mass of the Sun, but the radius of a city (10 km)

Part 1: Data

The procedure is the same, only the numbers are different!

MNS = 1.99 X 1030 kg

RS = 695,500 km

MNS = 1.99 X 1030 kg X 1000 gm / kg = 1.99 X 1033 grams

We must convert the radius into centimeters:

RNS = 695,500 km X (1000m / km) X (100cm / m) =12.7 X 10^30 km

18)

expected mass = 8(1.007825 ) + 8 (1.008665 ) = 16.13192 amu

B) mass defect = expected mass - actual mass

mass defect = 16.13192 - 15.994915

mass defect = 0.137005 amu

so the mass defect is 0.137005 u

C) binding energy = delta m x 931.5 MeV

B.E = 0.137005 x 931.5

B.E = 127.62 MeV

So the Binding energy is 127.62 MeV

19)

mass lost = mass of Rn - mass of alpha - mass of Po

mass lost = 222.017571 - 4.002603 -218.008930

mass lost = 6.038 x 10-3 u

energy released = mass lost x 931.5

energy released = 6.038 x 10-3 x 931.5

energy released = 5.624 MeV

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