I know that the potential for part C will be the same as that for a conducting s

Question

I know that the potential for part C will be the same as that for a conducting sheet and for part D it will be the same as that for a point charge. I don't understand why though. Please explain (10 points) A flat disk of radius R has a uniformly distributed charge o. A thin ring of radius r and thickness dr is shown in the figure A) (3 points) Calculate the infinitesimal electric field, dEx, along the x -axis due to the ring. Explain why B) (3 points) Calculate the electric field, E, along the x-axis C) (2 points) What is the electric field in the limit when due to the entire disk R/x 1. Is this result expected? Explain. Use the approximations on the reference sheet. D) (2 points) What is the electric field in limit when x/R

Explanation / Answer

For part (C) x/R <<1 which means that R >>x. Now this means that for a point very near the disc (small x in comparison to R) the disc will act like a plane sheet to that test charge placed at point x.

For part (D) R/x<<1 which means R<<x. Now when x is very very greater than R the disc will act like a point charge to test charge at point x.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.