How to find the total bits in cache, I found the professor\'s note and online so

Question

How to find the total bits in cache, I found the professor's note and online source example, the answers are different, which one is correct one?

Suppose direct-mapped cache has 64KB data and one word blocks,(32-bit memory address)How many total bits does it contain?

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Professor solution is:

number of cache slots = 64KB/4B = 16K

cache index = log (16K) = 14 bits

number of bits in tag = 32 - 14 -2 = 16

each cache slot contains 1 + 16 + 32 = 49 bits

total bits in cache = 49 * 16k

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textbook:

Explanation / Answer

the professor's note is correct

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