As inputs, assume $a0 = a; $a1 = b. Explain the following MIPS code by commentin

Question

As inputs, assume $a0 = a; $a1 = b.
Explain the following MIPS code by commenting each line of instruction, and descript
the functionality ($v0 = ?)
add $t0, $zero, $zero
loop: beq $a1, $zero, done
add $t0, $t0, $a0
sub $a1, $a1, 1
j loop
done: addi $t0, $t0, 100
add $v0, $t0, $zero

Explanation / Answer

add $t0, $zero, $zero -->here you add $zero + $zero into $t0 loop: beq $a1, $zero, done --->here the loop begins it goes until $a1 == $zero add $t0, $t0, $a0 -->here you add $a0 into $t0, t+=a c equivalent. sub $a1, $a1, 1 ---> here you substract -1 from $a1 j loop ---> goto the loop done: addi $t0, $t0, 100 ---> add + 100 into $t0 , addi is Add immediate add $v0, $t0, $zero --> add $t0 and $zero into the $v0 register.

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