We have the followingscore data, the last one represents the end of mark, not th

ID: 3616155 • Letter: W

Question

We have the followingscore data, the last one represents the end of mark, not thedata.

72,23,38,86,62,29,99,96,67,78,87,76,65,58,86,69,93,34,45,55

52, 7,74,48,83,39,90,18,82,26,65,53,39,96,66,-1

(a). Calculate theaverage score of the data.

(b).Count the number ofdata in each interval. The difference between each interval is 10point.

That is

0~9, 10~19, 20~29,30~39, 40~49,50~59, 60~69,70~79, 80~89, 90~100

(c). Count thenumber of data above the average and below theaverage.

(d).The output formatwill be:

*****SCOREREPORT*****

MEAN =##.###

ABOVE MEAN= ##

BELOW MEAN= ##

0~ 9: *

10~ 19: *

20~ 29: ***

30~ 39: ****

40~ 49: **

50~ 59: ****

60~ 69: ******

70~ 79: ****

80~ 89: ****

90~100: *****

please rate - thanks #include #include using namespace std; int main() {double average; int num[50],i=0,above=0,below=0,count[10]={0},j,sum=0,k; cout

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