1) Determine the SNR (dBs) for a received signal power, Pr=-10dBm, and a receive
ID: 3588811 • Letter: 1
Question
1)
Determine the SNR (dBs) for a received signal power, Pr=-10dBm, and a receiver noise, N=-203dBm?
a. Pr(dBm)*N(dBm)= 2.03E3 dBm
b. Pr(dBm)/N(dBm)= 49.26 dBm
c. Pr(dBm)+N(dBm)= -213 dBm
d. Pr(dBm)-N(dBm)= 193 dBm
2)
What is the noise temperature for a receiver operating at a temperature of T=305oK and frequency bandwidth of the receiver is B=4kHz? (N=kTB)
a. 1.68E-17 watts or -167.7dBW
b. 1.68E-14 watts or -167.7dBW
c. 1.22E+14 watts or +139dBW
d. 4.07E+21 watts or +204dBW
3)
The Signal-to-Noise Ratio (SNR or S/N) can be represented in decibel or non-decibel form. Select the correct decibel format where the use of brackets (i.e., [ ]) signifies dB values.
a. [N]/[S]
b. [S]/[N]
c. [S] - [N]
d. [S] + [N]
4)
Given the following information, what is the power received (Rx) at the receiver? Tx=50dBm, FSL=-50dB, given the equation: Rx(dBm) = Tx(dBm) + FSL(dBs)
a. Rx = 100 dBW
b. Rx = 0 dBm
c. Rx = -100dBm
d. Rx = 30 dBW
5)
45 dBW = _________mW
a. 3.16E7 mW
b. 3.16E4 mW
c. 75 mW
d. 45 mW
a. Pr(dBm)*N(dBm)= 2.03E3 dBm
b. Pr(dBm)/N(dBm)= 49.26 dBm
c. Pr(dBm)+N(dBm)= -213 dBm
d. Pr(dBm)-N(dBm)= 193 dBm
2)
What is the noise temperature for a receiver operating at a temperature of T=305oK and frequency bandwidth of the receiver is B=4kHz? (N=kTB)
a. 1.68E-17 watts or -167.7dBW
b. 1.68E-14 watts or -167.7dBW
c. 1.22E+14 watts or +139dBW
d. 4.07E+21 watts or +204dBW
3)
The Signal-to-Noise Ratio (SNR or S/N) can be represented in decibel or non-decibel form. Select the correct decibel format where the use of brackets (i.e., [ ]) signifies dB values.
a. [N]/[S]
b. [S]/[N]
c. [S] - [N]
d. [S] + [N]
4)
Given the following information, what is the power received (Rx) at the receiver? Tx=50dBm, FSL=-50dB, given the equation: Rx(dBm) = Tx(dBm) + FSL(dBs)
a. Rx = 100 dBW
b. Rx = 0 dBm
c. Rx = -100dBm
d. Rx = 30 dBW
5)
45 dBW = _________mW
a. 3.16E7 mW
b. 3.16E4 mW
c. 75 mW
d. 45 mW
Explanation / Answer
1.option d
Pr(dBm)-N(dBm)= 193 dBm
2.option b
3.option b
s/N
4.option c
5.option a
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