The position x as a function of time of a particle that moves along a straight l

Question

The position x as a function of time of a particle that moves along a straight line is given by: x(t) = -0.1t^4 + 0.8t^3 + 10t - 70 m The velocity v(t) of the particle is determined by the derivative of x(t) with respect to t, and the acceleration a(t) is determined by the derivative of v(t) with respect to t. Derive the expressions for the velocity and acceleration of the particle, and make plots of the position velocity, and acceleration as a function of time for 0 lessthanorequalto t lessthanorequalto 8 s. Use the subplot command to make the three plots on the same page with the plot of the position on the top, the velocity in the middle, and the acceleration at the bottom. Label the axes appropriately with the correct units.

Explanation / Answer

Answer

Below is the requires Matlab code:

syms t
x=-0.1*t.^4+0.8*t.^3+10*t-70
x=(-0.1*t.^4)+(0.8*t.^3)+(10*t)+70
vel=diff(x)
acc=diff(vel)
t=0:0.1:8-0.1;
X=subs(x,t);
V=subs(vel,t);
A=subs(acc,t);
figure, plot(t,X,t,V,'r',t,A,'g')
legend(' Position','Velocity','Acceleration')

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