The position of a particle moving alongthe x axis is given in centimeters by x·9

Question

The position of a particle moving alongthe x axis is given in centimeters by x·9.16 1.06 t where t is in seconds. Calculate a) the average velocity during the time interval t = 2.00 s to t = 3.00 s; (b) the instantaneous velocity at t . 2.00 s; (c) the instantaneous velocity at t = 3.00 s, (d) the instantaneous veoety at t-2.50 s; and (e) the instantaneous velocity when the particle is midway between its positions at t-2.00 s and t- 3.00 s (a) Number [20.14 (b) Numbef [12.72 (c) Number[28.62 (a) Numbe 19,875 (e) Number cm/s cm/s units units cm/s cm/s Units [ cm/s LINK TO SAMPLE PROBLEN INK TO SAMPLE PROBLEM LINK TO 1EX

Explanation / Answer

At t=2

x2= 9.16+1.06*2^3= 17.64

At t=3

X3= 9.16+1.06*3 ^3= 37.78 m

Midway position is

X= (37.78+17.64)/2= 27.71 m

Putting in displacement equation

27.71= 9.16+ 1.06t^3

t= 2.6

Instantaneous velocity

V= 3.18*t^2= 3.18*2.6^2

V= 21.5 m/s

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