Two 2KB EPROMs arc used to make a 4KB memory. How many address lines arc needed
ID: 3560383 • Letter: T
Question
Two 2KB EPROMs arc used to make a 4KB memory. How many address lines arc needed for the EPROMs? What upper address lines must be used for the decoder? For the memory of Question 9, what is the address of the last memory location, if the starting address of the EPROM is E4000? Design a memory address decoder for the EPROM memory of Question 10, using a circuit similar to that in Figure 9.10. Repeat Questions 9 through 11 for these memory sizes and starting addresses: 8KB, base address of CC000 32KB, base address of 80000 256KB, base address of 00000 Design a partial-address decoder for a 64KB EPROM with a base address of 40000. What are the ranges of addresses for the partial-address decoders of Example 9.7?Explanation / Answer
10) Address of last memory:
4Kb = 4 x 210 = 1000(H)
Base address = E4000(H).
Total = E4000 + 1000 - 1 = E4FFF
Therefore memory starts at location E4000 to E4FFF.
Last memory location is E4FFF.
12a) Following similar procedure as above,
8Kb = 8 x 210 = 2000(H)
Base address = CC000(H).
Total = CC000 + 2000 - 1 = CDFFF
Therefore memory starts at location CC000 to CDFFF.
Last memory location is CDFFF.
12b)
32Kb = 32 x 210 = 8000(H)
Base address = 80000(H).
Total = 80000 + 8000 - 1 = 87FFF
Therefore memory starts at location 80000 to 87FFF.
Last memory location is 87FFF.
12c)
256Kb = 256 x 210 = 40000(H)
Base address = 00000(H).
Total = 00000 + 40000 - 1 = 3FFFF
Therefore memory starts at location 00000 to 3FFFF.
Last memory location is 3FFFF.
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