Two 14.0 cm -diameter electrodes 0.55 cm apart form a parallel-plate capacitor.

Question

Two 14.0 cm -diameter electrodes 0.55 cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 14 Vbattery. After a long time, the capacitor is disconnected from the battery but is not discharged.

What is the charge on each electrode right after the battery is disconnected?

What is the electric field strength inside the capacitor right after the battery is disconnected?

What is the potential difference between the electrodes right after the battery is disconnected?

Explanation / Answer

Here,    charge on each electrode = 8.854 * 10-12 * 3.14 * 0.07 *0.07* 14/0.0055

                                                        =    3.467 * 10-10 C

electric field strength inside the capacitor   = 14/ 0.0055

                                                                     =   2545.45 N/C

potential difference between the electrodes = 14 V

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