hi. you will write a program that prompts the user to input 3 lower -case string

Question

hi. you will write a program that prompts the user to input 3 lower -case strings(of the type string). the program should then report a series os statistics about these strings .Specifically , the program should report which of the three strings is the last alphabetically, which one is the longest in length and finally a concatenation of the three strings( in alphabetical order) HINTS: (1) string concatenation ( the proccesing of appending one string to the back of another) (2) you need to make sure you include the string library. make sure you make good use of if and else statements to make decisions regarding the input string thank you

Explanation / Answer

//using no arrays

#include<iostream>

#include<string>

using namespace std;

int main(){

string str1,str2,str3;

string AlphaLast;

string longest;

string combined;

//get 3 strings

cout<<"You would need to enter three lower-case strings separately. ";

cout<<"Enter string #1: ";

getline(cin,str1);

cout<<"Enter string #2: ";

getline(cin,str2);

cout<<"Enter string #3: ";

getline(cin,str3);

//get alpahbetical last

if(str1.compare(str2)>=0 && str1.compare(str3)>=0){//str1 last

AlphaLast=str1;

if(str2.compare(str3)>=0)

combined=str3+str2+str1;

else

combined=str2 + str1 + str1;

}

else if(str2.compare(str1)>=0 && str2.compare(str3)>=0){//srt 2 last

AlphaLast=str2;

if(str3.compare(str1)>=0)

combined=str1 + str3 + str2;

else

combined=str3 + str1 + str2;

}

else{//str3 last

AlphaLast=str3;

if(str1.compare(str2)>=0)

combined=str2 + str1 + str3;

else

combined=str1 + str2 + str3;

}

//get longest

if(str1.length()>str2.length())

longest=str1;

else

longest=str2;

if(longest.length()<str3.length())//if str3 is greater

longest=str3;

//print stats

cout<<"statistics: ";

cout<<"longest string: "<<longest<<endl;

cout<<"alphabetically last: "<<AlphaLast<<endl;

cout<<"concatenation alphaetically: "<<combined;

return 0;

}

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