It is known that the manx allele in cats is an autosomal recessive lethal and is

Question

It is known that the manx allele in cats is an autosomal recessive lethal and is abbreviated "M". The manx allele interferes with normal spinal development, and cats with one copy of the manx allele have no tail (Manx is dominant for the tailless phenotype). A manx homozygote has extreme developmental abnormalities and does not survive. Normal cats have a tail and the normal allele is abbreviated "m". You are studying this trait in a population of wild cats

You observe that in the initial generation (G0), there are:

403 manx (tailless) cats

663 normal cats

You observe that in G1, there are:

306 manx (tailless) cats

689 normal cats.

1) What is the fitness of the heterozygote?

2) Using the fitness of the heterozygote calculated above, what is the predicted frequency of the M allele in G2?

Explanation / Answer

Answer

1) fitness is ability of survival through generations = 306/403 = 0.759 and 663/689= 0.962

avg fitness = 0.759 + 0.962 = 0.860 Ans

2) Allele frequencies do not change over generations.
*Genotype frequencies can be predicted from alleles

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