A freequency distribution is shown below. Complete parts (a) through (e). The nu
ID: 3390434 • Letter: A
Question
A freequency distribution is shown below. Complete parts (a) through (e).
The number of overtime hourss worked in one week per employee
overtime hours 0 1 2 3 4 5 6
Employees 7 18 27 57 44 33 15
a) Use the frequency distribution to construct a probablity distribution.
x P(x)
0 ?
1 ?
2 ?
3 ?
4 ?
5 ?
6 ?
(Round to the nearest thousandth as needed)
B) Find the mean of the probability distribution.
u= ? ( Round to the nearest tenth as needed.)
C) Find the variance of the probability distribution.
o^2=? (round to the nearest tenth as needed.)
d) Find the standard deviation of the probabiliity distribution.
0= ? ( Round to the nearest tenth a neeeded.)
e) Interpret the results in the context of the real-life situation.
a) An employee workks an average of 1.5 overtime hours per week with a standard diviation of approximately 3.4 hours.
b) Ann employeee works an average 3.4 of overtime hours per week with a standard deviation of approximately 7 hours.
c) An employee works an average of 3.4 overtime hours per week with a standard deviation of approximately 1.5 hours.
d) An employee works an average of 2.2 overtime hours per week with a standard deviation of approximately 1.5 hours.
Explanation / Answer
Mean is 3.4 mostly in the middle of the x value. Hence not skewed much.
But not fully symmetrical.
----------------------------------
a) c) An employee works an average of 3.4 overtime hours per week with a standard deviation of approximately 1.5 hours.
is the answer
0 7 0.034826 0 0 1 18 0.089552 0.089552 0.089552 2 27 0.134328 0.268657 0.537313 3 57 0.283582 0.850746 2.552239 4 44 0.218905 0.875622 3.502488 5 33 0.164179 0.820896 4.104478 6 15 0.074627 0.447761 2.686567 201 1 3.353234 13.47264 Mean 3.353 3.4 Variance 2.22846 2.2 Std dev 1.492803 1.5Related Questions
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