1- A test is made of versus . A sample of size is drawn, and . The population st
ID: 3372199 • Letter: 1
Question
1- A test is made of versus . A sample of size is drawn, and . The population standard deviation is . Compute the value of the test statistic z and determine if H0 is rejected at the level.
Question options:
A)
2.47, H0 rejected
B)
0.28, H0 not rejected
C)
0.28, H0 rejected
D)
2.47, H0 not rejected
Question options:
A)
B)
C)
D)
Question options:
A)
B)
C)
D)
5- About 29% of all burglaries are through an open or unlocked door or window. A sample of 130 burglaries indicated that 87 were not via an open or unlocked door or window. At the 0.05 level of significance, can it be concluded that this differs from the stated proportion?
Question options:
A)
B)
C)
D)
A)
No, because the test value -0.45 falls in the critical region.B)
No, because the test value -0.06 falls in the critical region.C)
Yes, because the test value -3.21 falls in the critical region.D)
Yes, because the test value -0.06 falls in the critical region.Explanation / Answer
Result:
2- Nationwide, the average waiting time until a electric utility customer service representative answers a call is 360 seconds. The Gigantic Kilowatt Energy Company randomly sampled 50 calls and found that, on average, they were answered in 335 seconds with a population standard deviation of 55 seconds. Can the company claim that they are faster than the average utility at f1q11g1.jpg?_&d2lSessionVal=D6SvtGAxb2Np
Question options:
A) No, because the test value -0.45 falls in the critical region.
B) No, because the test value -0.06 falls in the critical region.
Answer: C) Yes, because the test value -3.21 falls in the critical region.
D)Yes, because the test value -0.06 falls in the critical region.
Lower tail test
Z Test of Hypothesis for the Mean
Data
Null Hypothesis m=
360
Level of Significance
0.05
Population Standard Deviation
55
Sample Size
50
Sample Mean
335
Intermediate Calculations
Standard Error of the Mean
7.7782
Z Test Statistic
-3.2141
Lower-Tail Test
Lower Critical Value
-1.645
p-Value
0.0007
Reject the null hypothesis
3- Find the critical values for the following values of the significance f1q12g1.jpg?_&d2lSessionVal=D6SvtGAxb2Np, sample f1q12g2.jpg?_&d2lSessionVal=D6SvtGAxb2Np, and alternate hypothesis H1.
f1q12g3.jpg?_&d2lSessionVal=D6SvtGAxb2Np, f1q12g4.jpg?_&d2lSessionVal=D6SvtGAxb2Np, f1q12g5.jpg?_&d2lSessionVal=D6SvtGAxb2Np
Question options:
A)-2.998, 2.998
B)-3.355, 3.355
Answer: C)-3.499, 3.499
D)- 1, 345
5- About 29% of all burglaries are through an open or unlocked door or window. A sample of 130 burglaries indicated that 87 were not via an open or unlocked door or window. At the 0.05 level of significance, can it be concluded that this differs from the stated proportion?
Question options:
A)There is not enough information to draw a conclusion.
B)No. There is not enough evidence to support the claim that the proportion of open or unlocked window or door burglaries differs from 29%.
Answer: C)Yes. There is enough evidence to support the claim that the proportion of open or unlocked window or door burglaries differs from 29%.
D) None of the above.
Z Test of Hypothesis for the Proportion
Data
Null Hypothesis p =
0.29
Level of Significance
0.05
Number of Items of Interest
87
Sample Size
130
Intermediate Calculations
Sample Proportion
0.6692
Standard Error
0.0398
Z Test Statistic
9.5290
Two-Tail Test
Lower Critical Value
-1.9600
Upper Critical Value
1.9600
p-Value
0.0000
Reject the null hypothesis
Z Test of Hypothesis for the Mean
Data
Null Hypothesis m=
360
Level of Significance
0.05
Population Standard Deviation
55
Sample Size
50
Sample Mean
335
Intermediate Calculations
Standard Error of the Mean
7.7782
Z Test Statistic
-3.2141
Lower-Tail Test
Lower Critical Value
-1.645
p-Value
0.0007
Reject the null hypothesis
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