0. A survey found that women\'s heights are normally distributed with mean 62.6
ID: 3371127 • Letter: 0
Question
0. A survey found that women's heights are normally distributed with mean 62.6 in. and standard deviation 2.2 in. The survey also found that men's heights are normally distributed with a mean 67.7 in. and standard deviation 2.9. Complete parts a through c below. a. Most of the live characters at an amusement park have height requirements with a minimum of 4 ft 8 in. and a maximum of 6 ft 4 in. Find the percentage of women meeting the height requirement The percentage of women who meet the height requirement is (Round to two decimal places as needed.) b. Find the percentage of men meeting the height requirement. The percentage of men who meet the height requirement is (Round to two decimal places as needed.) C. If the height requirements are changed to exclude only the tallest 5% of men and the shortest 5% of women, what are the new height requirements? in. and at most The new height requirements are at least (Round to one decimal place as needed.) in. d: 13 Correct 12 Partial Credit 0 Question 3 (1/1) Question 7 (1/1) Question 11 (1/1) Question 4 (1/1) Question 8 (1/1) Question 12 (1/1) 10 (0/1)Explanation / Answer
Answer with explanation below:
A.
P(56<x<76) = p( 56-62.6/2.2< 76-62.6/2.2)
= P(-3<z<2.46)
= .9931-.0013
= .9918
Percentage is 99.18%
B. P(56<X<76)
= P(56-67.7/2.9 < x< 76-67.7/2.9)
= P(-4.034<z<2.86)
= .9979-0
= 99.79 percent of men clear the requiements
C. Maximum is 67.7+1.645*2.9= 72.47( we take men params)
Minimum is 56-1.645*2.2= 52.38( we take women params)
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