0% Prob Set 1 Problem Set 1: Wet Gases in Air. percent of all of the gases At no
ID: 1045089 • Letter: 0
Question
0% Prob Set 1 Problem Set 1: Wet Gases in Air. percent of all of the gases At normal body temperture (37"C), water vapor partial pressure is about 0.062 atm, or 6 How many mg of H20 are in a L of exhaled air? The amount of water dissolved in air is positively correlated with the temperature of the air. How many mg of H20 are in: 1 L of tropical beach air (100% rh) ? 1 L of of Lake Tahoe air (100% rh)? 1 L of steam? Show your work as you provide the amount of water in mg for each of those 4 types of air Responses Reply Showing All Responses " ordered by Newest Responses wExplanation / Answer
At any temperature, water vapour will be present in the air. There is a limit to the amount of water vapour which can exist in equilibrium with the air (the saturation pressure). The mass of water vapour in a unit volume of moist air is known as the absolute humidity (measured in g/m^3).
HA = mw / Vnet
The mg of water dissolved is 62000mg.
Relative humidity is also approximately the ratio of the actual to the saturation vapour pressure.
Relative humidity is the ratio of the air's water vapour content (amount actually in the air) to its water vapour capacity at a given temperature, expressed as a percent.
The general formula is: Relative Humidity (%) = (Water vapor content / Water vapor capacity) * 100%
For 37°C the water vapour capacity is: 37 grams/kilogram
RH given is 100 %
Therefore 100 (%) = water vapour content / 37 * 100
Then, water vapour content is also 37 g / kg
volume
v?=?w ? ?
? = density of air
v= volume of air
w = weight of air
x = 1 / 1.25
x = 0.8 L
37 g of water vapour present in 0.8 L of air.
So, in 1 Lof air, amount of water vapour present is:
37 * 100mg* 1/0.8
= 4625 mg of water is dissolved in 1 L of both the lakes.
Relative Humidity = (Actual Vapor Pressure) / (Saturation Vapor Pressure) * 100%
Amount of water is proportional to temperature. Since, relative humidity for two is same, therefore, mg of H2O present would be same in the two type of air.
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