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Ubability. selected hous has fewer thal Cip (c) What is the probability that a r

ID: 3369771 • Letter: U

Question

Ubability. selected hous has fewer thal Cip (c) What is the probability that a randomly sprobab? t unit has from four to six (inclusive) rooms? ted hoy probability selected hou unit has at least two rooms? Interpret this Nw 31. A Deck of Cards A standard deck of cards contod as shown in Figure 9. One card is randomlyste (d) What is the probability that a randomly se S2 selected from (a) Compute the probability of randomly selectingh he art club from a deck of cards. (b) Compute the probability of randomly selecting a club or diamond from a deck of cards. (c) Compute the probability of randomly selecting an a ace or heart from a deck of cards. 32. A Deck of Cards A standard deck of cards co cards, as shown in Figure 9. One card is randomly select ed f the deck. a) Compute the probability of randomly selecting a twoo three from a deck of cards ) Compute the probability of randomly selecting a two three or four from a deck of cards Compute the probability of randomly selecting a two from a deck of cards. Birthdays Exclude leap years from the following ulations Compute the probability that a randomly selected loes not have a birthday on November 8 Compute the probability that a randomly selected

Explanation / Answer

31. a) probability of selecting a heart is 1/4, probability of selecting a club is also 1/4 so the probability of selecting a heart OR a club is
1/4 + 1/4 = 2/4 = 1/2.

b) probability of selecting a diamond is also 1/4 so the probability of selecting any of those is
1/4 + 1/4 + 1/4 = 3/4

c) probability of selecting heart is 1/4
probability of selecting a ace is 4/52 = 1/13

HOWEVER, we can take one of the ace away because it is the ace of hearts so the probability of selecting the ace of diamonds, spades or clubs is
1/52 + 1/52 + 1/52 = 3/52.

So the probability of selecting either of the above is:
3/52 + 1/4 = 3/52 + 13/52 = 16/52 = 8/26 = 4/13