2. Given Problem 15, what is the observed value of t? 2.05, -2.49, -2.05, or 2.4
ID: 3365116 • Letter: 2
Question
2. Given Problem 15, what is the observed value of t? 2.05, -2.49, -2.05, or 2.49
3. Given Problem 15, what is the critical value of t? +-2.49, -2.49, 2.05, or 2.49
4. Given Problem 15, what is the probability (P) value of the test? -0.026, 0.974, 0.026, or 0.01
5. Given Problem 15, what is the conclusion?
a) fail to reject H0 and conclude the training is not effective
b) fail to reject H0 and conclude the training is effective
c) reject H0 and conclude the training is not effective
d) reject H0 and conclude the training is effective
a) fail to reject H0 and conclude the training is not effective
b) fail to reject H0 and conclude the training is effective
c) reject H0 and conclude the training is not effective
d) reject H0 and conclude the training is effective
Q Search Sheet data15-2 Home Insert Page Layout Formulas Data Review View -Insert Delete Format General 11 A- Av Wrap Text Calibri (Body) , Sort & 4-eT |+, Merge & Center, $, % , +00+00 Conditional Format Cell Formatting as Table Styles Paste F10 ID 334 378 473 493 473 394 401 451 431 451 473 399 Sheet1 + 100% ReadyExplanation / Answer
1. Correct Answer: Option (A) 25
since 26-1 = 25df
2. Correct Answer: Option (C) -2.05,
since
Test Statistic, t: -2.0457
3.Correct Answer: Option (D) 2.049
since Test Statistic, t: -2.0457
4.Correct Answer: Option (C) 0.026
P-Value: 0.0257
5.
Correct Answer: b) fail to reject H0 and conclude the training is effective
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