Appendix B Data Sets at 7: Bears (measurements from STATDISK: Data set name is B

Question

Appendix B Data Sets at 7: Bears (measurements from STATDISK: Data set name is Bean anesthetilzed wild bears) MEa coded with I- male and 2- fcnale, HEADLEN i Worksheet name is BEARS Mrw Workbook name is BEARS.XLS App name is BEARS and the flk names ase the ame as for e files eths, MONTH is the month of measurement (1 T-8V84 Plas January), SEX hs), HEADWTH is width of head (inches), NECK Text file names BAGE, BMNTH, BSEX BHDLN, BHDWD, a isunce and nock ún lache), LENGTH is length of body ünchal CHEST a distance around chest (inches), and WEIGHT is mcasured in pounds. Dara are from Gary Alk and Minitah, Inc BNECK, BLEN, BCHST,BWGHT 20 675450344 17010.0 65 220 62035.016 70 21.0700410220 265 73s 410 640 38.0 204 440 33 135 60 180 58.0 310 144 290 730 0 T 0 10 tas 6332.0 140 290 105 390 204 125 0175 903902 130 10 120 sa 4.0 215 590 180 580 300 16.0 61.0 33o 240 430 340 116 100 175 60.5 600 61.0 310 116 34S 13.0 95 6S 480 295 150 145 50 17 0 5 64.0 65.0 10 115 13.0 165 65 140 65 0 80 30 135 65 155 70 2.0 70550.0365 11.5 10 10 47.0 21.0 10 10 10 21.5 60.0 500 380 615 440 8s 23.0 635440 212 35 41.0 260 150 525 28.0 45 10.0 43240 115 50 170 30 305 11 45 13.0 46.0 155 80 305 750 540 514 125 85 180 73328140

Explanation / Answer

a. Hypothesis H0: p=.5 vs H1: p not equal .5

Under null, we have equal probability for being male or female

We shall do all coding in r

prop.test(x, p=c(.5,.5))

2-sample test for given proportions with continuity correction

data: x, null probabilities c(0.5, 0.5)

X-squared = 4.1667, df = 2, p-value = 0.1245

alternative hypothesis: two.sided

b. Mean of males= 199.7 , mean of females: 151.8

Welch Two Sample t-test

data: x1 and x2
t = 1.5596, df = 49.38, p-value = 0.1252
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-13.80953 109.61104
sample estimates:
mean of x mean of y
199.7429 151.8421

c. Standard deviation: Male= 134.0541, Female: 90.37.

F test to compare two variances

data: x1 and x2
F = 2.2, num df = 34, denom df = 18, p-value = 0.0785
alternative hypothesis: true ratio of variances is not equal to 1
95 percent confidence interval:
0.9104503 4.7811616
sample estimates:
ratio of variances
2.200011

d. For checking equality, we don't have equal no of observation for both the male and the female. Also, we are not taking AGE into account which will largely affect the outcome.

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